1/3(4)^x-7=2

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Solution for 1/3(4)^x-7=2 equation: 



1/3(4)^x-7=2

We move all terms to the left:

1/3(4)^x-7-(2)=0



Domain of the equation: 34^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/34^x-9=0

We multiply all the terms by the denominator


-9*34^x+1=0

Wy multiply elements

-306x+1=0

We move all terms containing x to the left, all other terms to the right

-306x=-1

x=-1/-306

x=1/306

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